Optimal. Leaf size=716 \[ \frac {2 (e+f x)^2 \text {ArcTan}\left (e^{c+d x}\right )}{b d}-\frac {2 a^2 (e+f x)^2 \text {ArcTan}\left (e^{c+d x}\right )}{b \left (a^2+b^2\right ) d}-\frac {a (e+f x)^2 \log \left (1+\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right ) d}-\frac {a (e+f x)^2 \log \left (1+\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right ) d}+\frac {a (e+f x)^2 \log \left (1+e^{2 (c+d x)}\right )}{\left (a^2+b^2\right ) d}-\frac {2 i f (e+f x) \text {PolyLog}\left (2,-i e^{c+d x}\right )}{b d^2}+\frac {2 i a^2 f (e+f x) \text {PolyLog}\left (2,-i e^{c+d x}\right )}{b \left (a^2+b^2\right ) d^2}+\frac {2 i f (e+f x) \text {PolyLog}\left (2,i e^{c+d x}\right )}{b d^2}-\frac {2 i a^2 f (e+f x) \text {PolyLog}\left (2,i e^{c+d x}\right )}{b \left (a^2+b^2\right ) d^2}-\frac {2 a f (e+f x) \text {PolyLog}\left (2,-\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right ) d^2}-\frac {2 a f (e+f x) \text {PolyLog}\left (2,-\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right ) d^2}+\frac {a f (e+f x) \text {PolyLog}\left (2,-e^{2 (c+d x)}\right )}{\left (a^2+b^2\right ) d^2}+\frac {2 i f^2 \text {PolyLog}\left (3,-i e^{c+d x}\right )}{b d^3}-\frac {2 i a^2 f^2 \text {PolyLog}\left (3,-i e^{c+d x}\right )}{b \left (a^2+b^2\right ) d^3}-\frac {2 i f^2 \text {PolyLog}\left (3,i e^{c+d x}\right )}{b d^3}+\frac {2 i a^2 f^2 \text {PolyLog}\left (3,i e^{c+d x}\right )}{b \left (a^2+b^2\right ) d^3}+\frac {2 a f^2 \text {PolyLog}\left (3,-\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right ) d^3}+\frac {2 a f^2 \text {PolyLog}\left (3,-\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right ) d^3}-\frac {a f^2 \text {PolyLog}\left (3,-e^{2 (c+d x)}\right )}{2 \left (a^2+b^2\right ) d^3} \]
[Out]
________________________________________________________________________________________
Rubi [A]
time = 0.79, antiderivative size = 716, normalized size of antiderivative = 1.00, number of steps
used = 32, number of rules used = 10, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.385, Rules used = {5686, 4265,
2611, 2320, 6724, 5692, 5680, 2221, 6874, 3799} \begin {gather*} -\frac {2 a^2 (e+f x)^2 \text {ArcTan}\left (e^{c+d x}\right )}{b d \left (a^2+b^2\right )}-\frac {2 i a^2 f^2 \text {Li}_3\left (-i e^{c+d x}\right )}{b d^3 \left (a^2+b^2\right )}+\frac {2 i a^2 f^2 \text {Li}_3\left (i e^{c+d x}\right )}{b d^3 \left (a^2+b^2\right )}+\frac {2 a f^2 \text {Li}_3\left (-\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{d^3 \left (a^2+b^2\right )}+\frac {2 a f^2 \text {Li}_3\left (-\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{d^3 \left (a^2+b^2\right )}-\frac {a f^2 \text {Li}_3\left (-e^{2 (c+d x)}\right )}{2 d^3 \left (a^2+b^2\right )}+\frac {2 i a^2 f (e+f x) \text {Li}_2\left (-i e^{c+d x}\right )}{b d^2 \left (a^2+b^2\right )}-\frac {2 i a^2 f (e+f x) \text {Li}_2\left (i e^{c+d x}\right )}{b d^2 \left (a^2+b^2\right )}-\frac {2 a f (e+f x) \text {Li}_2\left (-\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{d^2 \left (a^2+b^2\right )}-\frac {2 a f (e+f x) \text {Li}_2\left (-\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{d^2 \left (a^2+b^2\right )}+\frac {a f (e+f x) \text {Li}_2\left (-e^{2 (c+d x)}\right )}{d^2 \left (a^2+b^2\right )}-\frac {a (e+f x)^2 \log \left (\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}+1\right )}{d \left (a^2+b^2\right )}-\frac {a (e+f x)^2 \log \left (\frac {b e^{c+d x}}{\sqrt {a^2+b^2}+a}+1\right )}{d \left (a^2+b^2\right )}+\frac {a (e+f x)^2 \log \left (e^{2 (c+d x)}+1\right )}{d \left (a^2+b^2\right )}+\frac {2 (e+f x)^2 \text {ArcTan}\left (e^{c+d x}\right )}{b d}+\frac {2 i f^2 \text {Li}_3\left (-i e^{c+d x}\right )}{b d^3}-\frac {2 i f^2 \text {Li}_3\left (i e^{c+d x}\right )}{b d^3}-\frac {2 i f (e+f x) \text {Li}_2\left (-i e^{c+d x}\right )}{b d^2}+\frac {2 i f (e+f x) \text {Li}_2\left (i e^{c+d x}\right )}{b d^2} \end {gather*}
Antiderivative was successfully verified.
[In]
[Out]
Rule 2221
Rule 2320
Rule 2611
Rule 3799
Rule 4265
Rule 5680
Rule 5686
Rule 5692
Rule 6724
Rule 6874
Rubi steps
\begin {align*} \int \frac {(e+f x)^2 \tanh (c+d x)}{a+b \sinh (c+d x)} \, dx &=\frac {\int (e+f x)^2 \text {sech}(c+d x) \, dx}{b}-\frac {a \int \frac {(e+f x)^2 \text {sech}(c+d x)}{a+b \sinh (c+d x)} \, dx}{b}\\ &=\frac {2 (e+f x)^2 \tan ^{-1}\left (e^{c+d x}\right )}{b d}-\frac {a \int (e+f x)^2 \text {sech}(c+d x) (a-b \sinh (c+d x)) \, dx}{b \left (a^2+b^2\right )}-\frac {(a b) \int \frac {(e+f x)^2 \cosh (c+d x)}{a+b \sinh (c+d x)} \, dx}{a^2+b^2}-\frac {(2 i f) \int (e+f x) \log \left (1-i e^{c+d x}\right ) \, dx}{b d}+\frac {(2 i f) \int (e+f x) \log \left (1+i e^{c+d x}\right ) \, dx}{b d}\\ &=\frac {a (e+f x)^3}{3 \left (a^2+b^2\right ) f}+\frac {2 (e+f x)^2 \tan ^{-1}\left (e^{c+d x}\right )}{b d}-\frac {2 i f (e+f x) \text {Li}_2\left (-i e^{c+d x}\right )}{b d^2}+\frac {2 i f (e+f x) \text {Li}_2\left (i e^{c+d x}\right )}{b d^2}-\frac {a \int \left (a (e+f x)^2 \text {sech}(c+d x)-b (e+f x)^2 \tanh (c+d x)\right ) \, dx}{b \left (a^2+b^2\right )}-\frac {(a b) \int \frac {e^{c+d x} (e+f x)^2}{a-\sqrt {a^2+b^2}+b e^{c+d x}} \, dx}{a^2+b^2}-\frac {(a b) \int \frac {e^{c+d x} (e+f x)^2}{a+\sqrt {a^2+b^2}+b e^{c+d x}} \, dx}{a^2+b^2}+\frac {\left (2 i f^2\right ) \int \text {Li}_2\left (-i e^{c+d x}\right ) \, dx}{b d^2}-\frac {\left (2 i f^2\right ) \int \text {Li}_2\left (i e^{c+d x}\right ) \, dx}{b d^2}\\ &=\frac {a (e+f x)^3}{3 \left (a^2+b^2\right ) f}+\frac {2 (e+f x)^2 \tan ^{-1}\left (e^{c+d x}\right )}{b d}-\frac {a (e+f x)^2 \log \left (1+\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right ) d}-\frac {a (e+f x)^2 \log \left (1+\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right ) d}-\frac {2 i f (e+f x) \text {Li}_2\left (-i e^{c+d x}\right )}{b d^2}+\frac {2 i f (e+f x) \text {Li}_2\left (i e^{c+d x}\right )}{b d^2}+\frac {a \int (e+f x)^2 \tanh (c+d x) \, dx}{a^2+b^2}-\frac {a^2 \int (e+f x)^2 \text {sech}(c+d x) \, dx}{b \left (a^2+b^2\right )}+\frac {(2 a f) \int (e+f x) \log \left (1+\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right ) \, dx}{\left (a^2+b^2\right ) d}+\frac {(2 a f) \int (e+f x) \log \left (1+\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right ) \, dx}{\left (a^2+b^2\right ) d}+\frac {\left (2 i f^2\right ) \text {Subst}\left (\int \frac {\text {Li}_2(-i x)}{x} \, dx,x,e^{c+d x}\right )}{b d^3}-\frac {\left (2 i f^2\right ) \text {Subst}\left (\int \frac {\text {Li}_2(i x)}{x} \, dx,x,e^{c+d x}\right )}{b d^3}\\ &=\frac {2 (e+f x)^2 \tan ^{-1}\left (e^{c+d x}\right )}{b d}-\frac {2 a^2 (e+f x)^2 \tan ^{-1}\left (e^{c+d x}\right )}{b \left (a^2+b^2\right ) d}-\frac {a (e+f x)^2 \log \left (1+\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right ) d}-\frac {a (e+f x)^2 \log \left (1+\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right ) d}-\frac {2 i f (e+f x) \text {Li}_2\left (-i e^{c+d x}\right )}{b d^2}+\frac {2 i f (e+f x) \text {Li}_2\left (i e^{c+d x}\right )}{b d^2}-\frac {2 a f (e+f x) \text {Li}_2\left (-\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right ) d^2}-\frac {2 a f (e+f x) \text {Li}_2\left (-\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right ) d^2}+\frac {2 i f^2 \text {Li}_3\left (-i e^{c+d x}\right )}{b d^3}-\frac {2 i f^2 \text {Li}_3\left (i e^{c+d x}\right )}{b d^3}+\frac {(2 a) \int \frac {e^{2 (c+d x)} (e+f x)^2}{1+e^{2 (c+d x)}} \, dx}{a^2+b^2}+\frac {\left (2 i a^2 f\right ) \int (e+f x) \log \left (1-i e^{c+d x}\right ) \, dx}{b \left (a^2+b^2\right ) d}-\frac {\left (2 i a^2 f\right ) \int (e+f x) \log \left (1+i e^{c+d x}\right ) \, dx}{b \left (a^2+b^2\right ) d}+\frac {\left (2 a f^2\right ) \int \text {Li}_2\left (-\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right ) \, dx}{\left (a^2+b^2\right ) d^2}+\frac {\left (2 a f^2\right ) \int \text {Li}_2\left (-\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right ) \, dx}{\left (a^2+b^2\right ) d^2}\\ &=\frac {2 (e+f x)^2 \tan ^{-1}\left (e^{c+d x}\right )}{b d}-\frac {2 a^2 (e+f x)^2 \tan ^{-1}\left (e^{c+d x}\right )}{b \left (a^2+b^2\right ) d}-\frac {a (e+f x)^2 \log \left (1+\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right ) d}-\frac {a (e+f x)^2 \log \left (1+\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right ) d}+\frac {a (e+f x)^2 \log \left (1+e^{2 (c+d x)}\right )}{\left (a^2+b^2\right ) d}-\frac {2 i f (e+f x) \text {Li}_2\left (-i e^{c+d x}\right )}{b d^2}+\frac {2 i a^2 f (e+f x) \text {Li}_2\left (-i e^{c+d x}\right )}{b \left (a^2+b^2\right ) d^2}+\frac {2 i f (e+f x) \text {Li}_2\left (i e^{c+d x}\right )}{b d^2}-\frac {2 i a^2 f (e+f x) \text {Li}_2\left (i e^{c+d x}\right )}{b \left (a^2+b^2\right ) d^2}-\frac {2 a f (e+f x) \text {Li}_2\left (-\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right ) d^2}-\frac {2 a f (e+f x) \text {Li}_2\left (-\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right ) d^2}+\frac {2 i f^2 \text {Li}_3\left (-i e^{c+d x}\right )}{b d^3}-\frac {2 i f^2 \text {Li}_3\left (i e^{c+d x}\right )}{b d^3}-\frac {(2 a f) \int (e+f x) \log \left (1+e^{2 (c+d x)}\right ) \, dx}{\left (a^2+b^2\right ) d}+\frac {\left (2 a f^2\right ) \text {Subst}\left (\int \frac {\text {Li}_2\left (\frac {b x}{-a+\sqrt {a^2+b^2}}\right )}{x} \, dx,x,e^{c+d x}\right )}{\left (a^2+b^2\right ) d^3}+\frac {\left (2 a f^2\right ) \text {Subst}\left (\int \frac {\text {Li}_2\left (-\frac {b x}{a+\sqrt {a^2+b^2}}\right )}{x} \, dx,x,e^{c+d x}\right )}{\left (a^2+b^2\right ) d^3}-\frac {\left (2 i a^2 f^2\right ) \int \text {Li}_2\left (-i e^{c+d x}\right ) \, dx}{b \left (a^2+b^2\right ) d^2}+\frac {\left (2 i a^2 f^2\right ) \int \text {Li}_2\left (i e^{c+d x}\right ) \, dx}{b \left (a^2+b^2\right ) d^2}\\ &=\frac {2 (e+f x)^2 \tan ^{-1}\left (e^{c+d x}\right )}{b d}-\frac {2 a^2 (e+f x)^2 \tan ^{-1}\left (e^{c+d x}\right )}{b \left (a^2+b^2\right ) d}-\frac {a (e+f x)^2 \log \left (1+\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right ) d}-\frac {a (e+f x)^2 \log \left (1+\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right ) d}+\frac {a (e+f x)^2 \log \left (1+e^{2 (c+d x)}\right )}{\left (a^2+b^2\right ) d}-\frac {2 i f (e+f x) \text {Li}_2\left (-i e^{c+d x}\right )}{b d^2}+\frac {2 i a^2 f (e+f x) \text {Li}_2\left (-i e^{c+d x}\right )}{b \left (a^2+b^2\right ) d^2}+\frac {2 i f (e+f x) \text {Li}_2\left (i e^{c+d x}\right )}{b d^2}-\frac {2 i a^2 f (e+f x) \text {Li}_2\left (i e^{c+d x}\right )}{b \left (a^2+b^2\right ) d^2}-\frac {2 a f (e+f x) \text {Li}_2\left (-\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right ) d^2}-\frac {2 a f (e+f x) \text {Li}_2\left (-\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right ) d^2}+\frac {a f (e+f x) \text {Li}_2\left (-e^{2 (c+d x)}\right )}{\left (a^2+b^2\right ) d^2}+\frac {2 i f^2 \text {Li}_3\left (-i e^{c+d x}\right )}{b d^3}-\frac {2 i f^2 \text {Li}_3\left (i e^{c+d x}\right )}{b d^3}+\frac {2 a f^2 \text {Li}_3\left (-\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right ) d^3}+\frac {2 a f^2 \text {Li}_3\left (-\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right ) d^3}-\frac {\left (2 i a^2 f^2\right ) \text {Subst}\left (\int \frac {\text {Li}_2(-i x)}{x} \, dx,x,e^{c+d x}\right )}{b \left (a^2+b^2\right ) d^3}+\frac {\left (2 i a^2 f^2\right ) \text {Subst}\left (\int \frac {\text {Li}_2(i x)}{x} \, dx,x,e^{c+d x}\right )}{b \left (a^2+b^2\right ) d^3}-\frac {\left (a f^2\right ) \int \text {Li}_2\left (-e^{2 (c+d x)}\right ) \, dx}{\left (a^2+b^2\right ) d^2}\\ &=\frac {2 (e+f x)^2 \tan ^{-1}\left (e^{c+d x}\right )}{b d}-\frac {2 a^2 (e+f x)^2 \tan ^{-1}\left (e^{c+d x}\right )}{b \left (a^2+b^2\right ) d}-\frac {a (e+f x)^2 \log \left (1+\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right ) d}-\frac {a (e+f x)^2 \log \left (1+\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right ) d}+\frac {a (e+f x)^2 \log \left (1+e^{2 (c+d x)}\right )}{\left (a^2+b^2\right ) d}-\frac {2 i f (e+f x) \text {Li}_2\left (-i e^{c+d x}\right )}{b d^2}+\frac {2 i a^2 f (e+f x) \text {Li}_2\left (-i e^{c+d x}\right )}{b \left (a^2+b^2\right ) d^2}+\frac {2 i f (e+f x) \text {Li}_2\left (i e^{c+d x}\right )}{b d^2}-\frac {2 i a^2 f (e+f x) \text {Li}_2\left (i e^{c+d x}\right )}{b \left (a^2+b^2\right ) d^2}-\frac {2 a f (e+f x) \text {Li}_2\left (-\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right ) d^2}-\frac {2 a f (e+f x) \text {Li}_2\left (-\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right ) d^2}+\frac {a f (e+f x) \text {Li}_2\left (-e^{2 (c+d x)}\right )}{\left (a^2+b^2\right ) d^2}+\frac {2 i f^2 \text {Li}_3\left (-i e^{c+d x}\right )}{b d^3}-\frac {2 i a^2 f^2 \text {Li}_3\left (-i e^{c+d x}\right )}{b \left (a^2+b^2\right ) d^3}-\frac {2 i f^2 \text {Li}_3\left (i e^{c+d x}\right )}{b d^3}+\frac {2 i a^2 f^2 \text {Li}_3\left (i e^{c+d x}\right )}{b \left (a^2+b^2\right ) d^3}+\frac {2 a f^2 \text {Li}_3\left (-\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right ) d^3}+\frac {2 a f^2 \text {Li}_3\left (-\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right ) d^3}-\frac {\left (a f^2\right ) \text {Subst}\left (\int \frac {\text {Li}_2(-x)}{x} \, dx,x,e^{2 (c+d x)}\right )}{2 \left (a^2+b^2\right ) d^3}\\ &=\frac {2 (e+f x)^2 \tan ^{-1}\left (e^{c+d x}\right )}{b d}-\frac {2 a^2 (e+f x)^2 \tan ^{-1}\left (e^{c+d x}\right )}{b \left (a^2+b^2\right ) d}-\frac {a (e+f x)^2 \log \left (1+\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right ) d}-\frac {a (e+f x)^2 \log \left (1+\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right ) d}+\frac {a (e+f x)^2 \log \left (1+e^{2 (c+d x)}\right )}{\left (a^2+b^2\right ) d}-\frac {2 i f (e+f x) \text {Li}_2\left (-i e^{c+d x}\right )}{b d^2}+\frac {2 i a^2 f (e+f x) \text {Li}_2\left (-i e^{c+d x}\right )}{b \left (a^2+b^2\right ) d^2}+\frac {2 i f (e+f x) \text {Li}_2\left (i e^{c+d x}\right )}{b d^2}-\frac {2 i a^2 f (e+f x) \text {Li}_2\left (i e^{c+d x}\right )}{b \left (a^2+b^2\right ) d^2}-\frac {2 a f (e+f x) \text {Li}_2\left (-\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right ) d^2}-\frac {2 a f (e+f x) \text {Li}_2\left (-\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right ) d^2}+\frac {a f (e+f x) \text {Li}_2\left (-e^{2 (c+d x)}\right )}{\left (a^2+b^2\right ) d^2}+\frac {2 i f^2 \text {Li}_3\left (-i e^{c+d x}\right )}{b d^3}-\frac {2 i a^2 f^2 \text {Li}_3\left (-i e^{c+d x}\right )}{b \left (a^2+b^2\right ) d^3}-\frac {2 i f^2 \text {Li}_3\left (i e^{c+d x}\right )}{b d^3}+\frac {2 i a^2 f^2 \text {Li}_3\left (i e^{c+d x}\right )}{b \left (a^2+b^2\right ) d^3}+\frac {2 a f^2 \text {Li}_3\left (-\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right ) d^3}+\frac {2 a f^2 \text {Li}_3\left (-\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right ) d^3}-\frac {a f^2 \text {Li}_3\left (-e^{2 (c+d x)}\right )}{2 \left (a^2+b^2\right ) d^3}\\ \end {align*}
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Mathematica [A]
time = 6.78, size = 872, normalized size = 1.22 \begin {gather*} -\frac {-4 b d^2 e^2 \text {ArcTan}\left (e^{c+d x}\right )-4 i b d^2 e f x \log \left (1-i e^{c+d x}\right )-2 i b d^2 f^2 x^2 \log \left (1-i e^{c+d x}\right )+4 i b d^2 e f x \log \left (1+i e^{c+d x}\right )+2 i b d^2 f^2 x^2 \log \left (1+i e^{c+d x}\right )-2 a d^2 e^2 \log \left (1+e^{2 (c+d x)}\right )-4 a d^2 e f x \log \left (1+e^{2 (c+d x)}\right )-2 a d^2 f^2 x^2 \log \left (1+e^{2 (c+d x)}\right )+2 a d^2 e^2 \log \left (b-2 a e^{c+d x}-b e^{2 (c+d x)}\right )+4 a d^2 e f x \log \left (1+\frac {b e^{2 c+d x}}{a e^c-\sqrt {\left (a^2+b^2\right ) e^{2 c}}}\right )+2 a d^2 f^2 x^2 \log \left (1+\frac {b e^{2 c+d x}}{a e^c-\sqrt {\left (a^2+b^2\right ) e^{2 c}}}\right )+4 a d^2 e f x \log \left (1+\frac {b e^{2 c+d x}}{a e^c+\sqrt {\left (a^2+b^2\right ) e^{2 c}}}\right )+2 a d^2 f^2 x^2 \log \left (1+\frac {b e^{2 c+d x}}{a e^c+\sqrt {\left (a^2+b^2\right ) e^{2 c}}}\right )+4 i b d f (e+f x) \text {PolyLog}\left (2,-i e^{c+d x}\right )-4 i b d f (e+f x) \text {PolyLog}\left (2,i e^{c+d x}\right )-2 a d e f \text {PolyLog}\left (2,-e^{2 (c+d x)}\right )-2 a d f^2 x \text {PolyLog}\left (2,-e^{2 (c+d x)}\right )+4 a d e f \text {PolyLog}\left (2,-\frac {b e^{2 c+d x}}{a e^c-\sqrt {\left (a^2+b^2\right ) e^{2 c}}}\right )+4 a d f^2 x \text {PolyLog}\left (2,-\frac {b e^{2 c+d x}}{a e^c-\sqrt {\left (a^2+b^2\right ) e^{2 c}}}\right )+4 a d e f \text {PolyLog}\left (2,-\frac {b e^{2 c+d x}}{a e^c+\sqrt {\left (a^2+b^2\right ) e^{2 c}}}\right )+4 a d f^2 x \text {PolyLog}\left (2,-\frac {b e^{2 c+d x}}{a e^c+\sqrt {\left (a^2+b^2\right ) e^{2 c}}}\right )-4 i b f^2 \text {PolyLog}\left (3,-i e^{c+d x}\right )+4 i b f^2 \text {PolyLog}\left (3,i e^{c+d x}\right )+a f^2 \text {PolyLog}\left (3,-e^{2 (c+d x)}\right )-4 a f^2 \text {PolyLog}\left (3,-\frac {b e^{2 c+d x}}{a e^c-\sqrt {\left (a^2+b^2\right ) e^{2 c}}}\right )-4 a f^2 \text {PolyLog}\left (3,-\frac {b e^{2 c+d x}}{a e^c+\sqrt {\left (a^2+b^2\right ) e^{2 c}}}\right )}{2 \left (a^2+b^2\right ) d^3} \end {gather*}
Antiderivative was successfully verified.
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Maple [F]
time = 180.00, size = 0, normalized size = 0.00 \[\int \frac {\left (f x +e \right )^{2} \tanh \left (d x +c \right )}{a +b \sinh \left (d x +c \right )}\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] Both result and optimal contain complex but leaf count of result is larger than twice
the leaf count of optimal. 1411 vs. \(2 (659) = 1318\).
time = 0.41, size = 1411, normalized size = 1.97 \begin {gather*} \text {Too large to display} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (e + f x\right )^{2} \tanh {\left (c + d x \right )}}{a + b \sinh {\left (c + d x \right )}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {\mathrm {tanh}\left (c+d\,x\right )\,{\left (e+f\,x\right )}^2}{a+b\,\mathrm {sinh}\left (c+d\,x\right )} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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